Math, asked by vivekastronaut, 3 months ago


13. Heena takes a loan of 20,000 for 2 years at 15% p.a compound interest. She repays 12,000 at the end of the
first year. How much must she pay at the end of the second year to clear her debt?​

Answers

Answered by ZAYNN
7

Answer:

  • Principal = Rs. 20,000
  • Time = 2 years
  • Rate = 15%

According to the Question :

Rs. 20,000 × 15/100

______________________

⠀ Rs. 3000⠀⠀⠀ Rs. 3000

⠀⠀⠀⠀ Rs. 3000 × 15/100 = Rs. 450

⇒ Amount = Principal + CI

⇒ Amount = Rs. 20,000 + Rs. 6,000 + Rs. 450

⇒ Amount = Rs. 26,450

Henna should pay to clear debt :

⇒ Second year = Amount - First year

⇒ Second year = Rs. 26450 - Rs. 12000

Second year = Rs. 14,450

Answered by rastogikubair5
0

Answer:

Second Year = ₹14, 450

Step-by-step explanation:

A = P ( 1 + R/100)^n

Principal = ₹20,000

Rate = 15%

n = 2 years = Time

By putting the value;

A = 20,000 ( 1+15/100)^2

A = 20,000 (23/20)^2 [By Cancelling Out]

A = 20,000 × 23/20 × 23/20

A = ₹26,450

Second Year = Amount - First Year

Second Year = 26,450-12,000

Ans - Second year to clear = ₹ 14,1450.

Done by kubair.27 on Instagram...

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