A body is falling from a height of 300 m had 300J of potential energy at the highest point .What will be it's kinetic energy after falling from 100m from the highest point?
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Explanation:
ItsSamGupta
- (a). Mass of the Body = 10 kg.
- Height = 10 m.
- Acceleration due to gravity = 9.8 m/s².
- Using the Formula,Potential Energy = mgh
- = 10 × 9.8 × 10 = 980 J.
- (b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.
- ∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.
- ∴ Kinetic Energy = 980 J.
- (c). Kinetic Energy = 980 J.
- Mass of the ball = 10 kg.
- ∵ K.E. = 1/2 × mv²
- ∴ 980 = 1/2 × 10 × v²
- ∴ v² = 980/5
- ⇒ v² = 196
- ∴ v = 14 m/s.
Answered by
0
Answer:
100 J
Explanation:
by transformation of potential energy into kinetic energy
P. E. = K. E.
K. E. = 100J
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