Math, asked by wasimkhan1996, 4 months ago

13. If in a battle 70% of combantants lost on eye, 80% an ear, 75% arms, 85% a leg and x% lost
all four, then find the minimum value of x. ​

Answers

Answered by IIJustAWeebII
2

 \bf{ \large{ \red{ \boxed{ \boxed{Minimum \: value \: of \: x = 10\%}}}}}

 \green{ \mathfrak{ \large{ \underbrace{Solution}}}}

  • Combatants who lost eye = 70%

  • Combatants who lost ear = 80%

Minimum possible combatants who lost both eye and ear = 50%

{70% lost eyes and thus 30% are fine. In order to keep combatants with both injuries minimum let these 30% lost ear. Thus 50% combatants lost both. (80 - 30 = 50)}

Again,

  • Combatants who lost arm = 75%

  • Combatants who lost leg = 85%

Minimum possible combatants who lost both arm and leg = 60%

{AGAIN REASON IS SAME AS ABOVE}

Combatants who lost both eye and ear = 50%

Combatants who lost both arm and leg = 60%

Minimum possible soldiers who lost all 4 organs = 10%

 \sf{ \purple{Hence, \: the \: minimum \: value \: of \: x \: is \: 10\%}}

Hope this helps you mate✌

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