Question

13. If the distance between two points (0, 2) and (x,2) is 4,then find the value of x ?​

Answer 1

Answer:

The value of x is 4

Explanation:

Given :

The distance between two points (0 , 2) and (x , 2) is 4

To find :

the value of x

Solution :

The distance between two points (x₁ , y₁) and (x₂, y₂) is

$\sf D=\sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

Substitute

• x₁ = 0

• x₂ = x

• y₁ = 2

• y₂ = 2

The distance between the two points is given as 4.

$\sf 4=\sqrt{(x-0)^2+(2-2)^2} \\\\ \sf 4=\sqrt{x^2+0^2} \\\\ \sf 4=\sqrt{x^2} \\\\ \sf x=4$

Therefore, the value of x is 4

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COORDINATE GEOMETRY :

• Coordinates are a set of values that shows the position of a point in the coordinate plane.
• The abscissa is the x - axis value
• The ordinate is the y - axis value
• The point at which the two axes intersect is the origin.
• The Cartesian plane is divided into four quadrants by x - axis and y - axis

Quadrant 1 : (+x, +y)

Quadrant 2 : (-x, +y)

Quadrant 3 : (-x, -y)

Quadrant 4 : (+x, -y)