Question

13. In a class section A has 42 boys out of a total of 75 students section B has 60% girls in a total
student strength of 80 and section has two-third boys among 45 students. Find the aggregate
percentage of boys of the class​

Answer 1

Answer:52%

Step-by-step explanation:

Section A boys=42

Section B boys=80-(60% x80)

=32

Section C boys=2/3x45=30

Total students =75+80+45

=200

%age of aggregate Boys=(42+32+30)/200x100

=104/200x100

=52%

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Answer 2

Question:

In a class section A has 42 boys out of a total of 75 students section B has 60% girls in a total student strength of 80 and section C has two-third boys among 45 students. Find the aggregatepercentage of boys of the class.

Solution:

In a class section A has 42 boys out of a total of 75 students.

That is,

The total number of students in section A = 75

Number of boy students = 42

In a class section B has 60% girls in a total student strength of 80.

That is,

Total number of students in section B = 80

Percentage of girls = 60%

Now, The percentage of boys = Total percentage - Girls percentage

Percentage of boys = 100% - 60%

Percentage of boys = 40%

Number of boys = 40% of 80

Number of boys = 40/100 × 80

Number of boys = 32

In a class section C has two-third boys among 45 students.

That is,

Total number of students in section C = 45

Number of boys = 2/3 of 45

Number of boys = 2/3×45

Number of boys = 30

According to the question,

Total number of students in all sections = 75+80+45 = 200

Total number of boys in all sections = 42+32+30 = 104

Now, The percentage of boys = Total number of boys/Total number of students × 100%

Percentage of boys = 104/200×100%

Percentage of boys = 52%

Therefore the aggregate percentage of boys of the class is 52%.