Question

13. In Figure 9, ABCD is a rhombus in which ZABD = 40°. Find i. ZBAC ii. ZBCD iii. ZADC.​

Answer 1

Answer:

BAC BCD and ADC = 40°

because all angles of rhombus are equal

Answer 2

Answer:

1. We know that diagonals of rhombus intersect at 90°

so, L AOB = 90°

Now, L OAB + L AOB + L OBA = 280°

L OAB + 90° + 40° = 180°

L OAB + 130° =180°

L OAB= 180°–130°

L OAB= 50°

2. We know, DC || AB

So, L DCA = L CAB (alternate interior angles)

L DCA= 50°

3. In triangle ADB, AD = AB (sides of Rhombus are equal)

So, L ADB = L ABD = 40°

Now, L CDB = L ADB = 40° (alternate interior angles)

L ADC = L ADB + L CDB

= 40° + 40°

= 80°

Pls See :- L means angle

Step-by-step explanation:

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