Question

13.In the given figure ABC is a triangle in which AB=AC and D is a point on AB .Through D a line DE is drawn parallel to BC and meeting AC at E .Prove that AD=AE .​

Answer 1

Step-by-step explanation:

angle ADE = angle ABC

angle AED = angle ACB

These are corresponding angles

AB = AC

Therefore angle ABC = angle ACB

Therefore angle ADE = angle AED

Therefore AD = AE

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