Question

13 In two triangles DEF and PQR, if DE = QR, EF = PR and FD = PQ, then 1

a) ∆DEF ≅ ∆PQR b) ∆FED ≅ ∆PRQ c) ∆EDF ≅ ∆RPQ d) ∆PQR ≅ ∆EFD​

Answer 1

Answer:

b) ∆FED ≅ ∆PRQ

Step-by-step explanation:

D≈Q

E≈R

F≈P

Answer 2

Answer:

In DEF and PQR

DE=Qr

EF=PR

FD=PQ(given)

by sss postulate

DEF is congruent to PQR