Question

13. Mohit makes 8 full rounds of a rectangular field with length = 120 m and breadth = 75 m.
John makes 10 full rounds of a square field with each side 100 m. Find who covers larger
distance and by how much ?
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Answer 1

Mohit case

distance covered in one round is perimeter of the rectangle

=2(120+75)

2×195=390

distance covered in 8 rounds =8×390=3120m

John case

distance covered in one round is perimeter of the square

=4×100=400

distance covered in 10 rounds=10×400=4000m

as 4000>3120

so john covered more distance by 880m

Answer 2

Answer:

first, area of rectangle = l×b

=120×75

= 9000m*2

second area of square = side × side

=100×100

=10000m*2

therefore, john cover more distance than mohit by 1000m^2