Question

13
on
home
away with
the
I man
walks
straight
road from his
to
market 2.5 km
1 speed of 5 km/h. Finding
market closed, he instantly twins of
walks back home
with a speed
7.5 kmph. The avraga speed
of the man the interval of
time oto 40 min
(a) 5 km/h
25 Km/h (0 30 kalh @ 45 km/h
ove
b)​

Answer 1

Answer:

Explanation:

0 to 40 min

Speed of the man = 7.5 km/h

Distance travelled in first 30 min = 2.5 km

Distance travelled by the man (from market to home) in the next 10 min

= 7.5 × 10/60 = 1.25 km

Net displacement = 2.5 – 1.25 = 1.25 km

Total distance travelled = 2.5 + 1.25 = 3.75 km

Average velocity = Displacement / Time = 1.25 / (40/60) = 1.875 km/h

Average speed = Distance / Time = 3.75 / (40/60) = 5.625 km/h