13. Prove that
tan A + sec A-1
÷ tan A -secA +1=
tan A +sec A
Answers
Answered by
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Answer:
Step-by-step explanation:
LHS =
tanA + secA - 1
_____________
tanA - secA + 1
= tanA + secA - (sec˄2A - tan˄2A) [sec˄2A - tan˄2A = 1]
__________________________
tanA - secA + 1
= tanA + secA - {(secA - tanA) (secA + tanA)}
_________________________________
tanA - secA + 1
= (secA + tanA) (1- secA + tanA)
______________________
tanA - secA + 1
= secA + tanA
Hence Proved..
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