Question

13. Prove that
tan A + sec A-1
÷ tan A -secA +1=
tan A +sec A ​

Answer 1

Answer:

Step-by-step explanation:

LHS =

tanA +  secA - 1

_____________

tanA - secA + 1

=  tanA +  secA - (sec˄2A - tan˄2A)                          [sec˄2A - tan˄2A = 1]

   __________________________

                  tanA - secA + 1

= tanA + secA - {(secA - tanA) (secA + tanA)}

  _________________________________

                     tanA - secA + 1

= (secA + tanA) (1- secA + tanA)

    ______________________

             tanA - secA + 1

= secA + tanA

Hence Proved..