13. Show that the equation 2x2 -6x + 7= 0 cannot be satisfied by any real values of x.
Answers
Answered by
1
Answer:
this is the answer
Step-by-step explanation:
D=b
2
−4ac=0
=2[2(a+b)]
2
−2[2(a
2
+b
2
)][1]
=4(a+b)
2
−8(a
2
+b
2
)
=4a
2
+4b
2
+8ab−8a
2
−8b
2
=−4a
2
−4b
2
+8ab=−4(a−b)
2
must be less than zero
Hence no real roots.
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Answered by
0
Given: 2x²-6x+7=0
To find: Roots of given equation
Step-by-step explanation:
2x²-6x+7 = 0
a = 2 b = -6 c = 7
D = b²-4ac
= (-6)²-4(2)(7)
= 36 - 56
= -20
Since D<0,
therefore, real roots does not exist for the given equation.
Answer: Real roots does not exist for given equation.
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