Question

13. Sum of the ages of father and his son is 60 years. After 14 years, father's age will be three times the
om of the son. Find their present ages.​

Answer 1

Answer:

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Step-by-step explanation:

Let X = the present age of the father and Y = the present age of the son.

X+Y=60 so X=60-Y

X+14=3*(Y+14)

so X=3*(Y+14)-14

so X=3Y+28

Also, X=60-Y

So

60-Y=3Y+28

32=4Y

8=Y

X= 60-Y = 60-8 and so X=52

The present age of the father is 52 years old and the boy is 8 years old

Answer 2

GiVen:-

$\sf \: Father's \: age = x \: years$

$\sf \: Son's \: age = 60 - x$

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†${\underline{ \underline{\sf{\purple{After \: 14 \: years, }}}}}$

$\sf \: Father's \: age = ( x + 14 )$

$\sf \: Son's \: age = ( 60 - x + 14 ) \\ \sf \: = ( 74 - x )$

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AnSwer:-

$\star{ \frak{ \underline{According \: to \: the \: question, }}}$

$: \implies \sf \: \: \: x + 14 = 3 ( 74 - x ) \\ \\ : \implies \sf \: \: \:x + 14 = 222 - 3x\\ \\ : \implies \sf \: \: \:x + 3x = 222 - 14 \\ \\: \implies \sf \: \: \: 4x = 208 \\ \\ : \implies \sf \: \: \:x = \dfrac{208}{4} \\ \\: \implies \sf \: \: \: x = 52$

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$\therefore$ Present age's :

$\sf \: Father's \: age = x = 52 \: years$

$\sf \: Son's \: age = 60 - 52 \\ \sf= 8 \: years$