Question

13.
The sum of the ages of a man and his son is 45 years. Five years ago, the product of their
bo
ages was four times the man's age at the time. Find their present ages.
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Answer 1

Answer:

option =( D)

Step-by-step explanation:

(1). None of these

(2). Let the present ages of the father and son be 7x and 3x years respectively

Then, 7x * 3x = 756 <=> 21x2 = 75

<=> x2 = 36 <=> x = 6

Required ratio = (7x + 6) : (3x + 6) = 48 : 24 = 2 : 1.

Answer 2

Answer:

your answer is 9 and 36...... please mark me as brainliest and do follow me........

Step-by-step explanation:

LET FATHER'S AGE BE Y YEARS AND SON'S AGE BE X YEARS ... ..

GIVEN THAT,

X + Y = 45---------1

5 YEARS AGO,

(X - 5) (Y - 5) = 4 ( Y - 5)---------2

FROM 2

(X - 5 ) = 4(Y - 5)/(Y- 5)

X-5= 4

X= 9

PUT THE VALUE OF X IN EQUATION 1

9 + Y = 45

: . Y = 45 - 9

: . Y = 36

FATHER'S PRESENT AGE IS 36 YEARS AND SON'S PRESENT AGE IS 9 YEARS

HOPE IT HELPS YOU