Question

solve the pair of equations (5/x-1 +1/y-2=2) (6/x-1 - 3/y-2 =1) ​

Answer 1

Answer:

it is. or no just give me thanks if it correct frds

Answer 2

$(\frac{5}{x-1}+\frac{1}{y-2}=2)(\frac{6}{x-1}-\frac{3}{y-2})$

$[\frac{5(y-2)+1(x-1)}{(x-1)(y-2)}=2][\frac{6(y-2)-3(x-1)}{(x-1)(y-2)} =1]$

$[5(y-2)+1(x-1)=2(x+1)(y-2)][6(y-2)-3(x-1)=1(x-1)(y-2)]$

$(5y-10+x-1=2xy-4x+y-2)(6y-2y-3x+1=xy-2x-y=2)$

$(2xy+5y-y+x+4x-1+2=0)(xy-3x+2x-2y+y+1-2=0)$

$(2xy+4y+5x+1=0) (xy-1x-y-1=0)$

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