13. The sum of the digits of a two digit number is 7.If the digits are reversed, the number increased
by 3 equals 4 times the original number. Find the original number (Write the steps of working)
(3 Points)
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10 ȶɦǟռӄֆ﹢ʄօʟʟօա=ɨռɮօӼ
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Answer:
16 and 61
Step-by-step explanation:
Let the two digit number be 10x + y
The reversed number = 10y + x
According to the question
Part 1
Reversed number + 3 = 4(original number)
10y + x + 3 = 4(10x + y)
10y + x + 3 = 40x + 4y
3 = 39x - 6y
3(1) = 3(13x - 2y)
13x - 2y = 1 ----------------------------------(1)
Part 2
let the digits of the number be x,y
x + y = 7
x = 7 - y --------------------------------(2)
Substitute x value in equation (1)
13(7-y) - 2y = 1
91 - 13y - 2y = 1
91 - 15y = 1
90 = 15y
y = 6
x = 7 - y = 7 - 6 = 1
Therefore the original number is 10(1)+6 = 16
The reversed number is 61.
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