Question

13. The zeros
of x²-2x-8is
​

Answer 1

Answer:

x²-2x-8

x²+2x-4x-8

x(x+2)-4(x+2)

(x+2)(x-4)

x+2 = 0

x = -2

x-4 = 0

x = 4

Zeroes of x are = -2,4

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