Question

at btc = 9 and
abt bct ca = 26 then find
9² +6²+c²​

Answer 1

Step-by-step explanation:

ANSWER

We know (a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca

⇒(a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ca)

Given, a+b+c=9 and ab+bc+ca=26

Putting these values, we get

(9)

2

=a

2

+b

2

+c

2

+2(26)

⇒81=a

2

+b

2

+c

2

+52

⇒a

2

+b

2

+c

2

=81−52=29