Question

13. Three pieces of timber of lengths 63m , 42m and 35m, have to be divided into planks of the
length. What is the greatest possible length of each plank? How many planks are formed ?​

Answer 1

Answer:

20 pieces of 7 m

Step-by-step explanation:

Given

Three pieces of timber of lengths 63m , 42m and 35m

We need to find

Greatest possible length of each plank and their total numbers

Let's find prime factors of given numbers to identify divisibility of each:

• 63= 3*3*7
• 42= 2*3*7
• 35= 5*7

As per above, the three numbers have common divisor of 7. This is the greatest possible length of each piece. So each piece is of 7 m length.

Number of pieces is visible from the above: 3*3+2*3+5= 20 pieces

The answer is

20 pieces, 7m each

Answer 2

Answer:

hlo mate

20 paisa for 7 meter

mark it as brainliest