Question

13. Two particles of equal mass have
coordinates (2m, 4m, 6m)
and (6m, 2m, 8m). Of these one particle has a velocity
V = (2 i)ms' and another particle has velocity v2 = (2j) ms
at timet = 0. The coordinate of their centre of mass at time
t = 1s will be
(a) (4m, 4m, 7m)
(b) (5m, 4m, 7m)
(c) (2m, 4m, 6m)
(d) (4m, 5m, 4m)
​

Answer 1

The correct answer to your question is (b) 5m, 4m, 7m

❤Pls mark as brainliest if the answer is correct❤

Answer 2

Explanation:

First you add velocity to coordinates with respect to direction. Here, for first particle velocity was 2 in x direction and coordinate was (2,4,6) so by adding velocity to x coordinate, you get new coordinate (4,4,6). Do the same for second particle and then by taking individual new coordinates in Xcm, Ycm and Zcm formula you'll get coordinate of centre of mass as time is one no worries. Hope you understand.