(13+x)(13-x) how to do expansion of it
seemasoni88:
169-x^2
simple,
we just have to use a identity
which is (a-b)(a+b) = (a*a) - (b*b)
which is (a-b)(a+b) = (a*a) - (b*b)
yes it's cery simple
yes
Answers
Answered by
8
Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝
Step:-1
multiply 13 into (13-x)
Step:-2
multiply +x into. (13-x)
solution:-
13(13-x)+x(13-x)
169-13x+13x-x²
Arrange in particular form
-x²+169
As well as written
169-x²
that's all
Step:-1
multiply 13 into (13-x)
Step:-2
multiply +x into. (13-x)
solution:-
13(13-x)+x(13-x)
169-13x+13x-x²
Arrange in particular form
-x²+169
As well as written
169-x²
that's all
Answered by
16
Hey there!
Given ( 13 + x) ( 13 - x) is in the form of ( a + b) ( a - b)
So , ( a + b) ( a - b)
= a ( a + b ) - b ( a + b)
= a² + ab - ab - b²
= a² - b²
Now,
( 13 + x) ( 13 - x)
= ( 13² - x²)
= 169 - x²
Hope helped!
Given ( 13 + x) ( 13 - x) is in the form of ( a + b) ( a - b)
So , ( a + b) ( a - b)
= a ( a + b ) - b ( a + b)
= a² + ab - ab - b²
= a² - b²
Now,
( 13 + x) ( 13 - x)
= ( 13² - x²)
= 169 - x²
Hope helped!
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