13(y–4)–3(y–9)=5(y+4)solve the following questions in linear equations
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Answer:
13(y−4)−3(y−9)−5(y+4)=0
⇒13y−52−3y+27−5y−29=0
⇒5y−72+27=0
⇒5y=−45
⇒y= −45/5
⇒y=−9
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