Question

13 year back my father was thrice my age and 2 years back he was twice my age. The present age of my father is

Answer 1

Let my present age is x and my father's age is y

Then, 13 years back,

My father age was x-13
And my father's age was y-13

If 3(x-13)=y-13
3x-39=y-13
3x-y=26. -------1equation

Before two years my age was x-2 and my father age was y -2,

2(x-2)=y-2
2x-4=y-2
2x-y=2. -------2equation

Subtract both the equations

3x-y=26 -----1equation
2x-y=2. ------2equation
- + -

x=24

Put the value of x in ---2equation

2(24)-y=2

48-2=y

46=y

Then the my present age is 24 and father present age is 46,
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Verification,

My present age is 24, and my father's present age is 46,

Then, before 13 years,

3(24-13)=46-13

3*11=33

33=33

Before two years from now,
My age was
24-2=22

And my father's age was 46-2=44

2(22)=44

44=44

____________________

Hence proved that my age is 24 and my father's age is 46

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