mean of frist 10 even natural number is a 110 b 100 c 11 d 10
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a=2 , d=2.
sum of first 10 even natural numbers=
n/2{2a+(n-1)*d}
=10/2{2*2+(10-1)*2}
=110
so,
mean=110/10
=11
answer = 11
sum of first 10 even natural numbers=
n/2{2a+(n-1)*d}
=10/2{2*2+(10-1)*2}
=110
so,
mean=110/10
=11
answer = 11
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