Question

137
Astone of mass 200k g is thrown up with certain velocity reaches maximum height of
30m If another body of double the mass is thrown up with half de velocity of the first
then maximum height reached by its
1) som
2) 15mn
75m 4)3,5m
ALVA'S CET STUDY MATERIALI PUCPHYSICSVOL 1​

Answer 1

Given :

• Mass of stone = 200 g
• Maximum height reache by stone = 30 m

To Find :

• Maximum height reached by other body with double mass and half velocity than stone

Solution :

$\large\boxed{ \sf \blue{ {v}^{2} - {u}^{2} = 2as}} \\ \\ \sf Here,\: a = - g \\ \\ \sf At \: maximum \: point ,\: v = 0 \\ \\ \sf h \propto {u}^{2} \\ \\ \sf \frac{h_1}{h_2} = \frac{ {v_1}^{2} }{ {v_2}^{2} } = \frac{30}{h_2} = { \bigg( \frac{V}{ \frac{V}{2} } }\bigg)^{2} \\ \\\sf h_2 = \frac{30}{4} \\ \\ \large \boxed{\sf \green{ h_2 = 7.5 \: m}}$