Question

A mixture contains Substance A and substance is in the
ratio 7:9, if the total weight of the misture 4 48kg
blind the weight of substance in the mixture​

Answer 1

Step-by-step explanation:

Suppose the can initially contains 7x and 5x of mixtures A and B respectively.

Quantity of A in mixture left =(7x−

12

7

×9) litres =(7x−

4

21

) litres.

Quantity of B in mixture left =(5x−

12

5

×9) litres =(5x−

4

15

) litres.

∴

(5x−

4

15

)+9

(7x−

4

21

)

=

9

7

⇒

20x+21

28x−21

=

9

7

⇒252x−189=140x+147

⇒112x=336

⇒x=3.

So, the can contained 21 litres of A