Question

13x^2-41x-120 factorise.....please do it ASAP!!!!!!

Answer 1

13x² - 41x - 120
13x² - 65x + 24x - 120
13x(x - 5) + 24(x - 5)
(x - 5) (13x + 24)

Answer 2

Step-1 : Multiply the coefficient of the first term by the constant 13 • -120 = -1560

Step-2 : Find two factors of -1560 whose sum equals the coefficient of the middle term, which is -41 .

-1560
+
1
=
-1559

-780
+
2
=
-778

-520
+
3
=
-517

-390
+
4
=
-386

-312
+
5
=
-307

-260
+
6
=
-254

-195
+
8
=
-187

-156
+
10
=
-146

-130
+
12
=
-118

-120
+
13
=
-107

-104
+
15
=
-89

-78
+
20
=
-58

-65
+
24
=
-41

13x^2-41x-120
13x^2-65x+24x-120
13x (x-5)24 (x-5)
(13x+24)(x-5)