Question

13yz from -2yz Subtract it Fundamentally​

Answer 1

Answer:

all right, so far apart. Maybe I II plus J, which is basically one comma one to find the route we do one squared plus one squared, which is the square root of two. So then we go one over the square root of two off one comma one which is the square root of two over to come of the square root of two over too. So therefore, this X squared of two or two I was scared to over to J necks. For part B, we have iPods, J plus K, which is +111 This is equal to the square root of three. So if I multiply everything by this created three about square 23 I plus squared is B J plus the square root of three times uh, K. This is a square 23 divided by three weather with roll this through three divided by three match For part C, we have to I minus K. So that's 120 negative one. So 20 native one. This is square root of five. So that would be too over the square to five. I minus two over the square five K for part C and then finally we go party. Over here party is four i six j plus K. So there's the squared of 16 plus 36 plus 1 36 plus one, which is equal to the square root of Let's see 53. So therefore, our final answer is four over the square to 53 I plus six over the square root of 53 35 53 j minus K over the square root of 53.

Step-by-step explanation:

hope it's helpful

make me brainliest answer