Question

14-1/2{13+2-(7+5-2+3)}

Answer 1

HI,
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14−$\frac{1}{2}$(13+2−(7+5−2+3))

=14−$\frac{1}{2}$(15−(7+5−2+3))

=14−$\frac{1}{2}$(15−(12−2+3))

=14−$\frac{1}{2}$(15−(10+3))

=14−$\frac{1}{2}$(15−13)

=14−$\frac{1}{2}$(2)

=14−1

=13
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:)