Question

_+_=14
+ +
_ - _=10
=15 =16​

Answer 1

Answer:

Step-by-step explanation:

Let’s quickly write the equations

B1 + B2 = 14

B1 + B3 = 15

B2 + B4 = 16

B3 – B4 = 10

by adding all equations

B1 + B2 + B3 = (14 + 15 + 16 + 10 )/2 = 55/2 = 27.5

B3 = 27.5 – (B1 + B2) = 27.5 – 14 = 13.5 => B3 = 13.5

B2 = 27.5 – (B1 +B3) = 27.5 – 15 = 12.5 => B2 = 12.5

B1 = 14 – B2 = 14 – 12.5 = 1.5 => B1 = 1.5

B4 = B3 – 10 = 13.5 – 10 = 3.5 => B4 = 3.5

Answer 2

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B₁ + B₂ = 14

B₁ + B₃ = 15

B₂ + B₄ = 16

B₃– B₄ = 10

Concept:

First order equations include linear equations. In the coordinate system, the linear equations are defined for lines. A linear equation in one variable is one in which there is a homogeneous variable of degree 1 (i.e., only one variable). Multiple variables may be present in a linear equation. Linear equations in two variables, for example, are used when a linear equation contains two variables. For instance, 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3 are examples of linear equations.

Given:

B₁ + B₂ = 14

B₁ + B₃ = 15

B₂ + B₄ = 16

B₃– B₄ = 10

Find:

Find the values of the variables

Solution:

B₁ + B₂ = 14

B₁ + B₃ = 15

B₂ + B₄ = 16

B₃– B₄ = 10

by adding all equations

B₁ + B₂ + B₃ = (14 + 15 + 16 + 10 )/2 = 55/2 = 27.5

B₃ = 27.5 – (B₁ + B₂) = 27.5 – 14 = 13.5 => B₃ = 13.5

B₂ = 27.5 – (B₁ +B3) = 27.5 – 15 = 12.5 => B₂ = 12.5

B₁ = 14 – B₂ = 14 – 12.5 = 1.5 => B₁ = 1.5

B₄ = B3 – 10 = 13.5 – 10 = 3.5 => B₄ = 3.5

Therefore, B₁=1.5 ,B₂=12.5 , b₃=13.5 and B₄=3.5

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