Question

14+3{34-18-14}÷3[6×2+17-(2×7)]

Answer 1

14 +3{34 - 18 - 14} ÷ 3[6 × 2 + 17 - (2 × 7)]

= 14 +3{16 - 14} ÷ 3[6 × 2 + 17 - (2 × 7)]

= 14 +3{2} ÷ 3[6 × 2 + 17 - (2 × 7)]

= 14 +3{2} ÷ 3[6 × 2 + 17 - (14)]

= 14 +3{2} ÷ 3[12 + 17 - (14)]

= 14 +3{2} ÷ 3[29 - (14)]

= 14 +3{2} ÷ 3[15]

= 14 + 6 ÷ 3[15]

= 14 + 2[15]

= 14 + 30

= 44

Answer 2

To solve this question, we have to use the principle known as BODMAS which stands for Bracket Of Division Multiplication Addition Subtraction. This is the order in which we have to solve the equation.

Also, the precedence of solving brackets is

Square Brackets [] > Curly Brackets {} > Round Brackets/Parenthesis ()

So,

$14+3{34-18-14}\div 3[6\times 2+17-(2\times 7)]\\= 14+3{34-18-14}\div 3[6\times 2+17-14]\\= 14+3{34-18-14}\div 3[12+17-14]\\= 14+3{34-18-14}\div 3[29-14]\\= 14+3{34-18-14}\div 3[15]\\= 14+3{34-18-14}\div 45\\= 14+3{2}\div 45\\= 14+6\div 45\\= 14+ \frac{6}{45}\\= 14+\frac{2}{15}\\=14\frac{2}{15}$

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