Question

14. A 25 m long ladder is placed against a vertical
wall such that the foot of the ladder is 7 m from
the feet of the wall. If the top of the ladder slides
down by 4 m, by how much distance will the
foot of the ladder slide ?​

Answer 1

Answer:

The foot of the ladder will slide by 4 m

Answer 2

Answer: method 1

let, ABC a right angled triangle formed,

where AB = height of wall, AC= ladder (longest side), BC= dist. b/w feet of wall and foot of ladder

NOW,  let AB be 'x'

using pythagoras theorem,

x^2 = AC^2 + BC^2

you will get 26 m (approx)

NOW AS THE LADDER SLIDES DOWN ,

new height of wall = 26 - 4 = 22 m

length of ladder = 25 m

let, distance b/w wall and ladder increase by 'z' m

NOW, using pythagoras theorem,

22^2 = 25^2 + (7+x)^2

you will get a quadratic equation in ax^2 + bx + c = 0 form

then solving it you will get value of x