Question

14. A bus travels at y km per hour. It is going from Daspur to Beespur. After the bus has
travelled for 5 hours, Beespur is still 20 km away. Express the distance from Daspur to
Beespur using y
​

Answer 1

Answer:

$speed \: of \: bus = distance \div time \\ \\ y = \frac{distancd}{5} \\ distance = 5y \\ \\ total \: distance = 5y + 20$

Answer 2

Answer:

(5v + 20) km

Step-by-step explanation:

Distance travelled in 1 hour = 'y' km

Distance travelled after 5 hours = speed x time

                                                     = ( y x 5 ) km = 5y km

Distance remaining = 20 km

Distance from Daspur to Beespur = (5y + 20) km

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