Question

14. A certain sum of money is divided among A B and
C such that A gets half of what B and C together
get. B gets one-third of what A and C together get. If
A got 3500 more than B, then how much money was
divided?​

Answer 1

Answer:

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Step-by-step explanation:

The total money divided among A,B and C was

As per the problem, A gets half of the amount B and C together got:

So,2A=(B+C),

2A-B-C=0.......(1),

Again B gets one-third of the amount A and C together got.

So,  3B=(A+C),

3B-A-C=0.....(2),

Now from (i) and (ii) we can conclude,

2A-B-C=3B-A-C,

2A-B-3b+A=0,

3A+4B=0,

3(B+3500)-4(B)=0,(As,A got 3500 more than B),

3B+10500-4B=0,

B=10500,,

So B got 10500,

As A got 3500 more than B hence B got(10500+3500)

=14000,

As C = 2A-B  (//from equation (1))

C={28000-10500} =17500.

So the total money divided was (14000+17500+10500)=42000.

42000 money was divided.

Hope it helps you.//✔✔✔

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