Question

14. A chemical mixture requires two chemicals, A and B in proportion 3:2. The
mixture is to be prepared in a tank of capacity 50 litres.Pipe A can fill the tank
with chemical A in 15 mins and pipe B can fill the tank with chemical B in 30
mins.If both pipes are opened when the tank is empty,then for how long should
the pipes And B run to obtain the mixture?(in mins)​

Answer 1

Step-by-step explanation:

3:2 50lit

A 30lit B 20 lit

Timt taken by A to fill 50 lit is 15 min

Time taken by A to fi 30 lit is (15*30)/50=9 min

Time taken by B tl to fill 50 lit 30 min

Time taken by B tl to fill 20 lit (30*20)/50 =12min

A+B together 1/9+1/12=(4+3)/36=5 1/7 min