Math, asked by samrudh77, 2 months ago

14. A man is four times as old as his son. After 20 years, he will be twice as old as his
son at that time. Find their present ages.

who will give correct answer with explanation I will mark them as BRAINLIST

PLEASE ANSWER​

Answers

Answered by usernametaken8
4

Step-by-step explanation:

Let the age of son be x

Father's age = 4x

After 20 years,

Son's age = x + 20, Father's age = 4x + 20

According to question,

2×(x+20) = 4x + 20

=> 2x + 40 = 4x + 20

=> 2x = 20

=> x = 10 years(Son's age)

4x = 40 years(Father's Age)

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