Chemistry, asked by rajputarmansingh246, 6 months ago

14. Calculate the amount of work
done by 4 moles of an ideal gas at
298 K in a reversible isothermal
expansion from 20 litres to 40 litres.
(log2 = 0.3010).

Answers

Answered by kundanconcepts800

0

Answer:

Explanation:

Work done in a reversible isothermal process = -2.303 nRT log V2/V1

= -2.303×4×8.314×298log40/20

= 6.869KJ

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