Question

14. Fencing the compound of a house costs ₹5452. If the rate is ₹94 per metre, find the perimeter of the compound. If the breadth is 10 m, find its length.
Don't dare to spam.

Answer 1

Solution!!

Breadth of the compound of a house is given and we are asked to calculate the length. This proves that it is rectangular in shape. Information about fencing is given which means that we can calculate the perimeter easily.

Total cost of fencing = Rs 5452

Cost of fencing = Rs 94 per metre

Perimeter = Total cost of fencing ÷ Cost of fencing per metre

Perimeter = 5452 ÷ 94

Perimeter = 58 metre

Breadth = 10 metre

We can calculate the length with the perimeter formula of rectangle.

Perimeter = 2(Length + Breadth)

58 = 2(Length + 10)

58 ÷ 2 = Length + 10

29 = Length + 10

Length = 29 - 10

Length = 19 metre

Hence, the length of the compound is 19 metre.

Answer 2

⇝ Answer:

• Perimeter of compound = 58 m
• Length of compound = 19 m

❍ Given :-

• Fencing the compound of a house costs ₹5452
• Rate → ₹94 per metre
• Breadth = 10 m

❍ To Find :-

• Perimeter of compound
• Length of compound

❍ Solution :-

$\tt →Perimeter = \dfrac{Cost \: of \: fencing}{Rate \: of \: fencing}$

$\tt →Perimeter = \dfrac{5452}{94}$

$\tt →\fbox{Perimeter = 58 \: m}$

Hence the perimeter of compound is 58 cm.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Now,

$\tt \fbox{Perimeter = 2(l + b)}$

$\tt →58 = 2(l + 10)$

$\tt →58 = 2l + 20$

$\tt →58 - 20 = 2l$

$\tt →38 = 2l$

$\tt → Length= \dfrac{38}{2}$

$\tt →\fbox{Length = 19 \: m}$

Hence, length of compound is 19 m.