14. Find the area of the trapezium ABCD in which ABI/DC, AB = 18 cm, B = 2C = 90° ZC CD = 12 cm and AD = 10 cm. please help.
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Find the area of the trapezium ABCD in which AB||DC, AB=18 cm, ∠B=∠C=90
∘
, CD=12 cm and AD=10 cm.
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Trapezium ABCD is drawn in figure.
AE=(18−12) cm =6 cm
Δ AED is a right-angled Δ
∴(AD)
2
+(ED)
2
+(AE)
2
10
2
=h
2
+6
2
∴h=
100−36
h=8 cm
Area of trapezium=
2
1
×Sum of parallel sides×Distance between them.
=
2
1
(18+12)×8
=
2
1
(30)×8
=30×4 =120 cm
2
.
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