Question

14. Find the value of (a ^ 3 + b ^ 3 + c ^ 3 - 3abc)/(ab + bc + ca - a ^ 2 - b ^ 2 - c ^ 2) when a = - 5; b = - 6, c = 10​

Answer 1

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Answer 2

Answer:

a

2

+b

2

+c

2

−ab−bc−ca

a

3

+b

3

+c

3

−3abc

=

(a

2

+b

2

+c

2

−ab−bc−ca)

(a+b+c)(a

2

+b

2

+c

2

−ab−bc−ca)

=a+b+c

Step-by-step explanation:

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