14. Find the value of (a ^ 3 + b ^ 3 + c ^ 3 - 3abc)/(ab + bc + ca - a ^ 2 - b ^ 2 - c ^ 2) when a = - 5; b = - 6, c = 10
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Answer:
a
2
+b
2
+c
2
−ab−bc−ca
a
3
+b
3
+c
3
−3abc
=
(a
2
+b
2
+c
2
−ab−bc−ca)
(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)
=a+b+c
Step-by-step explanation:
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