Question

14. Find the zeroes of the quadratic polynomial x² + x - 12 and verify the relationship
between Zeics and the cocfficients.​

Answer 1

Answer:

Given:

• We have been given a polynomial x² + x - 12.

To Find:

• We need to find the zeroes of this polynomial.

Solution:

The given polynomial is x² + x - 12.

We can find the zeroes of this quadratic polynomial by the method of splitting the middle term.

We need to find tw aqo such numbers whose sum is 1 and product is -12.

Two such numbers are 4 and -3.

Substituting the values, we have

x² + 4x - 3x - 12 = 0

=> x(x + 4) - 3(x + 4) = 0

=> (x + 4) (x - 3) = 0

Either (x + 4) = 0 or (x - 3) = 0.

When (x + 4) = 0

=> x = -4

When (x - 3) = 0

=> x = 3

Hence, two zeroes of this polynomial are -4 and 3.

Now, we need to verify the relationship between the zeroes and coefficients, we have

A = -4

B = 3

Sum of zeroes ( A + B )

= -4 + 3

= -1

= -b/a _______(1)

Product of zeroes ( AB )

= -4 × 3

= -12

= c/a ________(2)

From equation 1 and 2 relationship between zeroes and coefficients is verified!!

[❤✔]✌

Answer 2

Answer:

The up answer is right and follow him and thanks his answers.

Explanation:

Fast do it.