Question

14.Forces P,4P,2P,6P act along the sides AB,BC,CD,DA of a square of side a then find the magnitude of the resultant force at A *

Answer 1

Step-by-step explanation:

The resultant of 4 vectors in X, Y direction are:

resultant in X direction is

3

P

−

P

=2

P

(in -ve x direction)

In y direction is

4

P

−2

P

=2

P

(in +ve y direction)

So, the net resultant force vector is

R

→

=2

P

→

+2

P

→

angle between both vectors is 90

So magnitude of resultant is 2

2

P in direction of 45

0

from positive y axis in IV quadrant.