Question

14. How many electrons would be required to
deposit 6.35 g of copper at the cathode during
the electrolysis of an aqueous solution of copper
sulphate ? (Atomic mass of copper = 63.5 u,
N = Avogadro's constant) :
(JEE Main-2014-Online)​

Answer 1

Mass of copper=6.35g

molar mass of copper=63.5g

n Factor of copper=2

F=96500C

$moles \times n = \frac{q}{f}$

moles=6.35/63.5=0.1

$q = 0.1 \times 2 \times 96500$

$q = 19300c$

we know that,

1C=1.6×10^-19 electrons

19300C

=19300×1.6×10^-19 electrons

=30880×10^-19 e-

I hope this helps ( ╹▽╹ )