Question

14.How much potassium chlorate should be heated to produce 2.24L of oxygen at NTP?

Answer 1

Answer:

Hey buddy...

Here's your answer ::::

Since, At NTP

122.55g of potassium chlorate = 22.4L of oxygen

so, X gm of potassium chlorate = 2.24L

therefore,

122.55/X = 22.4/2.24

=> X = 122.55/10

X = 12.255g

Hence, 12.255g of potassium chlorate will produce 2.24L of oxygen.

Hope it helps

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