Question

14. If cos A = 1/2 and sin B =1/√2 , find the
tan A-tan B
value of:
and B are from the same triangle.
1+tan A tan BHere angles A​

Answer 1

Answer:

$Value \:of \:tanA-tanB=\sqrt{3}-1$

Step-by-step explanation:

$Given \: cosA= \frac{1}{2}\\=cos 60 \degree$

$\implies A = 60 \degree$

$Given \: sin B= \frac{1}{\sqrt{2}}\\=sin 45\degree$

$\implies B= 45\degree$

$Now ,\\tanA-tanB\\=tan60\degree - tan 45\degree\\=\sqrt{3}-1$

Therefore,

$Value \:of \:tanA-tanB=\sqrt{3}-1$

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