14. If n(A - B) = 12, n(B - A) = 16 and n(A n B) = 5, find :
(i) n(A)
(ii) n(B)
(iii) n(AUB)
Answers
Answered by
2
Step-by-step explanation:
(i) n(A) = 12+5 = 17
(ii) n(B) = 16+5 = 21
(iii) n(AUB) = n(A) + n(B) - n(A n B)
=17 + 21 - 5
=33
Answered by
1
(i) n(A)
We know that, n(A)=n(A−B)+n(A∩B)
=12+5
=17
(ii) n(B)
We know that, n(B)=n(B−A)+n(A∩B)
n(B)
=16+5
=21
(iii) n(A∪B)
We know that, n(A∪B)=n(A)+n(B)−n(A∩B)
=17+21−5
=38−5
n(A∪B)=33
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