Question

In a cricket match, a batsman hits a boundry 6 times out of 30 balls he plays.
Find the probability that on a ball played :
(i) he hits boundry
(ii) he does not hit a boundry.

Answer 1

Given:  A batsman plays 30 balls in a cricket match, therefore total number of trials = 30

A number of events of hitting the boundary = 6

(i) The probability that he hits boundary, P = 6/30 = ⅕  

Hence, the probability that he hits boundary is ⅕ .

Number of balls in which he is not hitting the boundary = 30 - 6 = 24

(ii) The probability that he does not hit a boundary , P = 24/30 = ⅘  

Hence, the probability that he does not hit a boundary is ⅘ .

Extra information :  

Probability is the study of the chances of events happening.

Event:

A Possible outcome or combination of outcomes is called an event.

The probability of happening of an event always lies from 0 to 1.

The sum of all the probabilities of all possible outcomes of an experiment is 1.

Required probability = Number of trials in which the event E has happened / Total number of trials

 

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Answer 2

Answer:

Step-by-step explanation:

Given :-

Number of events of hitting the boundary = 6

Total Number of trials = 30

To Find :-

(i) he hits boundry

(ii) he does not hit a boundry.

Formula to be used :-

P(hits boundry)  = Number of times hits a boundry/Total number of balls played

P(does not hit a boundry) = 1 - P(hits boundry)

Solution :-

Putting all the values, we get

P(hits boundry)  = Number of times hits a boundry/Total number of balls

⇒ P(hits boundry)  = 6/30

⇒ P(hits boundry)  = 1/5

Now, P(does not hit a boundry) = 1 - P(hits boundry)

⇒ P(does not hit a boundry) = 1 - 1/5

⇒ P(does not hit a boundry) = 5 - 1/5

⇒ P(does not hit a boundry) = 4/5

Hence, the probability that he hits boundry  is 1/5 and he does not hit a boundry is 4/5.