Question

Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes :
If the three coins are simultaneously tossed again, compute the probability of :
(i) 2 heads coming up.
(ii) 3 heads coming up.
(iii) at least one head coming up.
(iv) getting more heads than tails.
(v) getting more tails than heads.

Answer 1

Answer:

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Answer 2

Given : Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes :

Outcome   Frequency

No head  → 14  

One head  → 38

Two heads →  36

Three heads  → 12

 

Here, three coins are tossed 100 times.

 We know that  Probability of an event = (Number of Favorable outcomes) / (Total Numbers of outcomes)

Total numbers of outcomes = 100.

(i) Number of outcomes having two heads  = 36

Probability of 2 Heads coming up = 36/100 = 0.36

(ii) Number of outcomes having three heads  = 12

Probability of 3 Heads coming up = 12/100 = 0.12

(iii) Number of outcomes having at least one head  = 38 + 36 + 12 = 86

Probability of at least one head coming up  = 86/100 = 0.86

(iv) Number of outcomes having more Heads than Tails = 36 + 12 = 48

Probability of getting more Heads than Tails = 48/100 = 0.48

(v) Number of outcomes having more tails than heads = 14 + 38 = 52

Probability of getting more tails than heads = 52/100 = 0.52

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