Question

Two coind are tossed simultaneously 500 times with the following frequencies of different outcomes:
Two heads: 95 times
One tail: 290 times
No head: 115 times
Find the probability of occurrence of each of these events.

Answer 1

Answer:

p(getting two heads) = 95/500

= 0.19

p( getting one tail ) = 290/500

= 0.58

p ( getting no head ) = 115 / 500

= 0.23

now checking ...

as, 0.19 + 0.58 + 0.23 = 1.00

hence the solution is correct...

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Answer 2

$\bigstar$ Given:

• Total number of trials = 500 times
• Number of trials in which the head happens = 95 times

• Number of trials in which the tail happens = 290 times
• Number of trials in which the no tail happens = 115 times

$\bigstar$ To Find:

• Compute the probability of head.
• Compute the probability of tail.
• Compute the probability of no head.

$\bigstar$ Solution:

We know that,

Probability of any event $= \frac{Number\: of\: favorable\: outcome}{Total\: number\: of\: trials}$

Total number of trials = 95 + 290 + 115 = 500

Now,

P(Getting two heads) $= \frac{95}{500} = \boxed{\underline{\underline{0.19}}}$

P(Getting one tail) $=\frac{290}{500} = \boxed{\underline{\underline{0.58}}}$

P(Getting no head) $=\frac{115}{500} = \boxed{\underline{\underline{0.13}}}$

Therefore, Probability of head is 0.19, tail is 0.58 and no head is 0.13.