Question

14. In APQR, PT is perpendicular to QR, PQ-10 cm, QT = 6 cm, TR - 15 cm. Find the value of sin x + tan y.​

Answer 1

Step-by-step explanation:

Given: PQ=10cm, PR=24cm

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse) 2

=(Base) 2

+(Perpendicular) 2

[By Pythagoras theorem]

⇒(QR) 2

=(PQ) 2

+(PR) 2

⇒x 2

=(10) 2

+(24) 2

⇒x 2

=100+576=676

⇒x= 676

=26cm

Thus, the length of QR is 26cm.

solution